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A capacity of capacity C(1) is charged u...

A capacity of capacity `C_(1)` is charged up to `V` volt and then connected to an uncharged capacitor of capacity `C_(2)`. Then final potential difference across each will be

A

`(C_(2))/(C_(1)+C_(2))V`

B

`(C_(1))/(C_(1)+C_(2))V`

C

`(C_(1)+C_(2))/(C_(2))`

D

`(C_(1)+C_(2))/(C_(1))V`

Text Solution

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The correct Answer is:
B
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