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Potential difference between two points `(V_(A) - V_(B))` in an electric field `E = (2 hat(i) - 4 hat(j)) N//C`, where `A = (0, 0)` and `B = (3m, 4m)` is

A

`10 V`

B

`-10 V`

C

`16 V`

D

`-16 V`

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The correct Answer is:
To find the potential difference between points A and B in the given electric field, we can follow these steps: ### Step 1: Understand the Electric Field and Coordinates The electric field is given as: \[ \mathbf{E} = 2 \hat{i} - 4 \hat{j} \, \text{N/C} \] Point A has coordinates \( A(0, 0) \) and point B has coordinates \( B(3 \, \text{m}, 4 \, \text{m}) \). ### Step 2: Set Up the Potential Difference Formula The potential difference \( V_A - V_B \) can be calculated using the formula: \[ V_A - V_B = - \int_A^B \mathbf{E} \cdot d\mathbf{r} \] where \( d\mathbf{r} \) is the differential displacement vector. ### Step 3: Define the Displacement Vector The displacement vector \( d\mathbf{r} \) can be expressed in terms of its components: \[ d\mathbf{r} = dx \hat{i} + dy \hat{j} \] ### Step 4: Calculate the Dot Product Now, calculate the dot product \( \mathbf{E} \cdot d\mathbf{r} \): \[ \mathbf{E} \cdot d\mathbf{r} = (2 \hat{i} - 4 \hat{j}) \cdot (dx \hat{i} + dy \hat{j}) = 2dx - 4dy \] ### Step 5: Set Up the Integral Substituting the dot product into the potential difference equation gives: \[ V_A - V_B = - \int_A^B (2dx - 4dy) \] ### Step 6: Determine the Path of Integration To integrate from point A to point B, we can move in the x-direction first and then in the y-direction. The limits for \( x \) will be from 0 to 3, and for \( y \) from 0 to 4. ### Step 7: Integrate the Expression The integral can be split into two parts: \[ V_A - V_B = - \left( \int_0^3 2 \, dx + \int_0^4 (-4) \, dy \right) \] Calculating the first integral: \[ \int_0^3 2 \, dx = 2x \bigg|_0^3 = 2(3) - 2(0) = 6 \] Calculating the second integral: \[ \int_0^4 -4 \, dy = -4y \bigg|_0^4 = -4(4) - (-4)(0) = -16 \] ### Step 8: Combine the Results Now, substituting back into the equation: \[ V_A - V_B = - (6 - 16) = - (6 - 16) = - (-10) = -10 \, \text{V} \] ### Final Result Thus, the potential difference between points A and B is: \[ V_A - V_B = -10 \, \text{V} \] ---
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DC PANDEY-ELECTROSTATIC POTENTIAL AND CAPACITORS-(A) Chapter exercises
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  2. The equivalent capacitance between the point A and C is given by

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  6. In Millike's oil drop experiment an oil drop carrying a charge Q is he...

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  7. There are four concentric shells A,B, C and D of radii a,2a,3a and 4a ...

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  8. A solid conducting sphere having a charge Q is surrounded by an unchar...

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  9. A point charge q is placed at a distance of r from the centre O of an ...

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  10. A hollow sphere of radius r is put inside another hollow sphere of rad...

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  11. Three plates A, B, C each of area 50 cm^(2) have separation 3 mm betwe...

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  12. A parallel plate capacitor with air as medium between the plates has a...

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  13. The capacities and connection of five capacitors are shown in the adjo...

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  14. A charge +Q is uniformly distributed over a thin ring of the radius R....

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  15. A parallel plate capacitor of capacitance C is connected to a battery ...

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  16. Condenser A has a capacity of 15 muF when it is filled with a medium o...

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  17. In the given if point C is connected to the earth and a potential of +...

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  18. A network of four capacitors of capacity equal to C(1) = C, C(2) = 2C,...

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  20. A charged oil drop of mass 2.5xx10^(-7)kg is in space between the two ...

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