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A hollow sphere of radius r is put insid...

A hollow sphere of radius r is put inside another hollow sphere of radius R. The charges on the two are +Q and -q as shown in the figure. A point P is located at a distance x from the common centre such that `r lt x lt R`. The potential at the point P is

A

`1/(4pi epsi_(0)) ((Q-q)/x)`

B

`1/(4pi epsi_(0)) (Q/R-q/r)`

C

`1/(4pi epsi_(0)) (Q/R-q/x)`

D

`1/(4pi epsi_(0)) (q/r-Q/x)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the electric potential at point P located at a distance \( x \) from the common center of two concentric hollow spheres with charges \( +Q \) and \( -q \), we will follow these steps: ### Step 1: Understand the Configuration We have two hollow spheres: - The inner sphere has a radius \( r \) and charge \( +Q \). - The outer sphere has a radius \( R \) and charge \( -q \). - The point P is located at a distance \( x \) from the center, where \( r < x < R \). ### Step 2: Determine the Potential Due to Each Sphere 1. **Potential due to the Outer Sphere (V1)**: - For a hollow sphere, the electric field inside the sphere is zero. Therefore, the potential inside the outer sphere (at point P) is constant and equal to the potential at its surface. - The potential \( V_1 \) due to the outer sphere at the surface is given by: \[ V_1 = \frac{kQ}{R} \] where \( k \) is the Coulomb's constant. 2. **Potential due to the Inner Sphere (V2)**: - The potential inside a hollow charged sphere is also constant and equal to the potential at its surface. - The potential \( V_2 \) due to the inner sphere at the surface is given by: \[ V_2 = \frac{k(-q)}{r} \] where \( -q \) is the charge on the inner sphere. ### Step 3: Calculate the Total Potential at Point P - The total potential \( V_P \) at point P is the sum of the potentials due to both spheres: \[ V_P = V_1 + V_2 \] Substituting the expressions for \( V_1 \) and \( V_2 \): \[ V_P = \frac{kQ}{R} + \frac{k(-q)}{r} \] Simplifying this gives: \[ V_P = \frac{kQ}{R} - \frac{kq}{r} \] ### Final Expression for the Potential at Point P Thus, the potential at point P is given by: \[ V_P = \frac{kQ}{R} - \frac{kq}{r} \]
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DC PANDEY-ELECTROSTATIC POTENTIAL AND CAPACITORS-(A) Chapter exercises
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  11. A network of four capacitors of capacity equal to C(1) = C, C(2) = 2C,...

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  14. A capacitor of 4 mu F is connected as shown in the circuit. The intern...

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  15. A parallel plate capacitor is made of two dielectric blocks in series....

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  16. A number of capacitors each of capacitance 1 muF and each one of whic...

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  17. A series combination of n(1) capacitors, each of value C(1), is charge...

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  18. Two charges +6 muC and -4 muC are placed 15 cm apart as shown. At what...

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  19. Assume that an electric field vec(E) = 30 x^(2) hat(i) exists in spac...

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  20. An electron initially at rest falls a distance of 1.5 cm in a uniform ...

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