The length of a wire of a potentiometer is 100 cm, and the e.m.f. of its standard cell is E volt. It is employed to measure the e.m.f. of a battery whose internal resistance is `0.5 Omega`. If the balance point is obtained at I = 30 cm from the positive end, the e.m.f. of the battery is .
where i is the current in the potentiometer wire.

Options

A. `(30E)/(100.5)`
B. `(30E)/(100-0.5)`
C. `(30(E-0.5i))/(100)`, where `i` is the current in the potentiometer wire
D. `(30E)/(100)`

Answer

D