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Three resistances 2 Omega, 3 Omega and 4...

Three resistances `2 Omega, 3 Omega` and `4 Omega` are connected in parallel. The ratio of currents passing through them when a potential difference is applied across its ends will be

A

`5:4:3`

B

`6:3:2`

C

`4:3:2`

D

`6:4:3`

Text Solution

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The correct Answer is:
D
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