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In a uniform ring of resistance R there ...

In a uniform ring of resistance `R` there are two points `A` and `B` such that `/_ ACB = theta`, where `C` is the centre of the ring. The equivalent resistance between `A` and `B` is

A

`(R(2pi-theta))/(4pi)`

B

`(R theta)/(2pi)`

C

`R(1-(theta)/(2pi))`

D

`(R )/(4pi^(2))(2pi-theta)theta`

Text Solution

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The correct Answer is:
D
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