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In a ammeter 0.2% of main current passes...

In a ammeter `0.2%` of main current passes through the galvanometer. If resistance of galvanometer is `G`, the resistance of ammeter will be

A

`(1)/(499)G`

B

`(499)/(500)G`

C

`(1)/(500)G`

D

`(500)/(499)G`

Text Solution

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The correct Answer is:
A
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