A beam of protons with a velocity `4 xx 10^(5) m//sec` enters a uniform magnetic field of `0.4 T` at an angle of `37^(@)` to the magnetic field. Find the radius of the helical path taken by proton beam. Also find the pitch of helix.
`sin 37^(@) = 3//5 cos 37^(@) = 4//5`. `m_(p) ~= 1.6 xx 10^(-27) kg`.

A beam of protons with a velocity 4 xx 10^(5) m//sec enters a uniform magnetic field of 0.4 T at an angle of 37^(@) to the magnetic field. Find the radius of the helium path taken by proton beam. Also find the pitch of helix. sin 37^(@) = 3//5 cos 37^(@) = 4//5 . m_(p) ~= 1.6 xx 10^(-27) kg .

A beam of protons with a velocity of 4 X 10 ^5 ms^(-1) enters a uniform magnetic field of 0.3 T. The velocity makes an angle of 60^@ with the magnetic field. Find the radius of the helicla path taken by the proton beam and the pitch of the helix.

A beam of protons with a velocity 4 xx 10^(5) m/sec enters a uniform magnetic field of 0.3 Testa at an angle of 60^(@) to the magnetic field. Find the radius of the helical path taken by the proton beam. Also find the pitch of the helix, which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation [Mass of proton = 1.67 xx 10^(-27) kg. charge on proton = 1.6 xx 10^(19)C ]

A beam of protons with speed 4times10^(3)m/s enters a uniform magnetic field of 0.3T at an angle 60^(@) to the magnetic field.The pitch of the resulting helical path of protons is close to?

A beam of protons moving with a velocity of 4 xx 10^(5) m/s enetrs a uniform magnetic field of 0.3 T at an angle of 60◦ with the magnetic field. What is the radius of the helical path described by the proton beam? [m_p=1.67 xx 10^(-27) kg and the charge on the proton =1.6 xx 10^(-19) C]

A proton moving withh a velocity 2.5xx10^(7)m//s enters a magnetic field of intensity 2.5T making an angle 30^(@) with the magnetic field. The force on the proton is

A proton moving with a velocity of 2.5 xx 10^(7) m/s , enter a magnetic feildof 2T, making an angle of 30◦ with the magnetic field. The force acting on the proton

A proton enter in a uniform magnetic field of 2.0 mT at an angle of 60degrees with the magnetic field with speed 10m/s. Find the picth of path

A proton moving with a velocity 3xx10^(5)m//s enters a magnetic field of 0.3 tesla at angle of 30^@ with the field. The radius of curvature of its path will be (e/m for proton =10^(8)C//kg )

A charged particle enters a uniform magnetic field with velocity vector at angle of 45^@ with the magnetic field. The pitch of the helical path followed by the particle is p. the radius of the helix will be