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A circular loop of mass m and radius r in X-Y plane of a horizontal table as shown in figure. A uniform magnetic field B is applied parallel to X-axis. The current I in the loop, so that its one edge just lifts from the table is

A

`(mg)/(pir^(2)B)`

B

`(mg)/(pirB)`

C

`(mg)/(2pirB)`

D

`(pirB)/(mgl)`

Text Solution

Verified by Experts

The correct Answer is:
B
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DC PANDEY-MAGNETIC FIELD AND FORCES-Taking it together
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