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The magnetic field at the centre of a ci...

The magnetic field at the centre of a circular coil carrying current I ampere is B. It the coil is bent into smaller circular coil of n turns then its magnetic field at the centre is B, the ratio between B' and B is

A

`1:1`

B

`n:1`

C

`n^(2):1`

D

`(n+1):1`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The magnetic field at the centre of current carrying coil is

    A
    `(mu_(0)ni)/(2r)`
    B
    `(mu_(0))/(2pi)(ni)/r`
    C
    `(mu_(0)ni)/(4r)`
    D
    `mu_(0)ni`

  • The magnetic field at centre of a hexagonal coil of side l carrying a current I is

    A
    `(sqrt(3) mu_(0) I)/(pi l)`
    B
    `(mu_(0)I)/(4 pi l)`
    C
    `(pi mu_(0) I)/(sqrt(3) l)`
    D
    zero

  • The magnetic field due to current carrying circular coil having n turns is

    A
    `n^(2)` times as large as that produced by a single turn
    B
    n times as large as that produced by a single turn
    C
    `(1)/(2)` -times as large as that produced by a single turn
    D
    will be same as that produced by a single turn

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