When a proton is released from rest in a room, it starts with an initial acceleration `a_(0)` towards west. When it is projected towards north with a speed `v_(0)` it moves with an initial accelaration `3a_(0)` towards west. The electric and the maximum possible magnetic field in the room
(i) `(ma_(0))/(e)`, towards west
(ii) `(2 ma_(0))/(ev_(0))`, downward
(iii) `(ma_(0))/(e)`, towards east
(iv) `(2ma_(0))/(ev_(0))`, upward

Options

A. `(ma_(0))/(e) "west"(2ma_(0))/(ev_(0))"up"`
B. `(ma_(0))/(e) "west"(2ma_(0))/(ev_(0))"down"`
C. `(ma_(0))/(e) "east"(3ma_(0))/(ev_(0))"up"`
D. `(ma_(0))/(e) "east"(3ma_(0))/(ev_(0))"down"`

Answer

b