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Due to the flow of current in a circular...

Due to the flow of current in a circular loop of radius `R`, the magnetic induction produced at the centre of the loop is `B`. The magnetic moment of the loop is (`mu_(0)`=permeability constant)

A

`(BR^(2))/(2pi mu_(0))`

B

`(2piBR^(2))/(mu_(0))`

C

`(BR^(2))/( 2pi mu_(0))`

D

`(2pi BR^(2))/(mu_(0))`

Text Solution

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The correct Answer is:
b
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