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A charged particle with a velocity 2xx10...

A charged particle with a velocity `2xx10^(3) ms^(-1)` passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is `1.5 t. the magnitude of electric field will be

A

`1.5xx10^(3) NC^(-1)`

B

`2xx10^(3)NC^(-1)`

C

`3xx10^(3)NC^(-1)`

D

`1.33xx10^(3)NC^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
c
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Knowledge Check

  • A charged particle moving with velocity 2 xx 10^(3) m"/"s passes undeflected through electric and magnetic fields. Magnetic field is 1.5 tesla. The electric field intensity is

    A
    `2xx10^(3)N"/"C`
    B
    `1.5xx10^(3)N"/"C`
    C
    `3xx10^(3)N"/"C`
    D
    `(2)/(3)xx10^(3)N"/"C`

  • A charged particle enters a uniform magnetic field perpendicular to it. The magnetic field

    A
    increases the `K.E.` of the particle
    B
    decreases the `K.E.` of the particle
    C
    changes the direction of motion of the particle
    D
    does both (a) and ( c)

  • A charged particle moving with velocity vis subjected to electric field E and magnetic field B. The particle will go undeflected if

    A
    E is perpendicular to B.
    B
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    C
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    D
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