A battery of emf 3 volt and internal resistance r is connected in series with a resistor of `55 Omega` through an ammeter of resistance `1 Omega`. The ammeter reads 50 mA. Draw the circuit diagram and calculate the value of r.

A battery of emf 3V and internal resistance r is connected in series with a resistor of 55 Omega through an ammeter of resistance 1 Omega . The ammeter reads 50 mA. Draw the circuit diagram and calculate the value of r.

A battery of emf 2 V and internal resistance r is connected in series with a resistor of 10Omega through an ammeter of resistance 2Omega . The ammeter reads 50 mA. Draw the circuit diagram and calculate the value of r.

A battery of emf 1.4 V and internal resistance 2 Omega is connected to a resistor of 100 omega resistance through an ammeter. This resistance of the ammeter is 4//3 Omega . A voltmeter has also been connected to find the potential difference across the resistor. a. Draw the circuit diagram. b. The ammeter reads 0.02 A . What is the resistance of the voltmeter? c. The voltmeter reads 1.1 V . What is the error in the reading?

A battery of e.m.f 10V and internal resistance 3Omega is connected to a resistor.If the current in the circuit is 0.5A,then the resistance of the resistor is

A battery of EMF 1.4 V and internal resistance 2Omega is connected to resistor of 100Omega resistance through an ammeter. The resistance of the ammeter is (4)/(3)Omega . A voltmeter is also connected to find potential difference across resistor. The ammeter reacds 0.02 A if resistance of voltmeter is 100x then x is

Three batteries having emfs and internal resistances as shown in figure are connected across a resistor of 2Omega . The reading of ammeter is

A 9000 Omega voltmeter is connected across a resistor R and an ammeter of ressistance 0.015 Omega in series. The voltmeter reads 117V and a ammeter reads 0.13A. Calculate the value of R and power input to R.