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Three cells of emf 2.0 v, 1.8 V and 1.5 ...

Three cells of emf 2.0 v, 1.8 V and 1.5 V are connected in series. Their internal resistances are `0.05 Omega, 0.7 Omega " and " 1 Omega` respectively. If the battery is connected to an external resistor of `4 Omega` via a very resistance ammeter, what would be the reading in the ammeter ?

Answer

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(a) Three cells of emfs, 1.5 V, 2.0V and 2.5 V are connected in series. Their internal resistance are 0.20 Omega, 0.15 Omega and 0.15 Omega respectively. The battery is connected to an external resistor of 5.5 Omega via a very low resistance ammeter, what would be the reading of ammeter? (b) If the three cells above were joined in parallel, would they be characterised by a definite emf and internal resistance (independent of their individual internal resistance )? If not, how will you obtain currents in different branches of the circuit ?

A battery is formed by connecting three cells in series . The emfs of cells are 5 V, 2.5 V and 1.5 V and their internal resistance are 0.5 Omega ,0.05 Omega and 0.45 Omega respectively. This battery is connected across a load resistance of 5 Omega what current will be supplied by the battery ? if the cell of emf 1.5 V were connected with reverse polarity then what would have been the current supplied by the battery ?

Knowledge Check

  • A battery of EMF E produces currents 4 A and 3 A when connected to external resistance 1 Omega and 2 Omega respectively. The internal resistance of the battery is

    A
    `0.5 Omega`
    B
    `2 Omega`
    C
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    D
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  • Two batteries with emf 12V and 13V are connected in parallel across a load resistor of 10Omega . The internal resistances of the two batteries are 1 Omega and 2 Omega respectively. The voltage across the load lies between

    A
    11.4V and 11.5V
    B
    11.7 V and 11.8V
    C
    11.6V and 11.7V
    D
    11.5 V and 11.6V

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    Three identical cells of emf 2 V and internal resistances 0.20 Omega are connected in series. The combination is further connected to an external resistor of 6 Omega . Calculate the current through 6 Omega resistor.

    Two cells of emf of 1.5 V and 2.0 V having internal resistances of 1 Omega and 2 Omega , respectively are connected in parallel so as to send current in the same direction through an external resistance of 5 Omega . Find the current in the external circuit.

    Two cells connected in series have electromotive force of 1.5 V each. Their internal resistances are 0.5 Omega and 0.25 Omega respectively. This combination is connected to a resistance of 2.25 Omega . Calculate the current flowing in the circuit and the potential differnce across the terminals of each cell.

    Two cells of emfs 1.5 V and 2.0 V having internal resistances 0.2 Omega and 0.3 Omega respectively are connected in parallel. Calculate the emf and internal resistance of the equivalent cell.

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    A battery of 9V is connected in series with resistors of 0.2 Omega, 0.3 Omega,0.4 Omega, 0.5 Omega and 0.12 Omega respectively. How much current would flow through the 12 Omega resistors?

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