Three cells of emf 2.0 v, 1.8 V and 1.5 V are connected in series. Their internal resistances are `0.05 Omega, 0.7 Omega " and " 1 Omega` respectively. If the battery is connected to an external resistor of `4 Omega` via a very resistance ammeter, what would be the reading in the ammeter ?

(a) Three cells of emfs, 1.5 V, 2.0V and 2.5 V are connected in series. Their internal resistance are 0.20 Omega, 0.15 Omega and 0.15 Omega respectively. The battery is connected to an external resistor of 5.5 Omega via a very low resistance ammeter, what would be the reading of ammeter? (b) If the three cells above were joined in parallel, would they be characterised by a definite emf and internal resistance (independent of their individual internal resistance )? If not, how will you obtain currents in different branches of the circuit ?

A battery is formed by connecting three cells in series . The emfs of cells are 5 V, 2.5 V and 1.5 V and their internal resistance are 0.5 Omega ,0.05 Omega and 0.45 Omega respectively. This battery is connected across a load resistance of 5 Omega what current will be supplied by the battery ? if the cell of emf 1.5 V were connected with reverse polarity then what would have been the current supplied by the battery ?

Three identical cells of emf 2 V and internal resistances 0.20 Omega are connected in series. The combination is further connected to an external resistor of 6 Omega . Calculate the current through 6 Omega resistor.

A battery of EMF E produces currents 4 A and 3 A when connected to external resistance 1 Omega and 2 Omega respectively. The internal resistance of the battery is

Two batteries with emf 12V and 13V are connected in parallel across a load resistor of 10Omega . The internal resistances of the two batteries are 1 Omega and 2 Omega respectively. The voltage across the load lies between