In the circuit diagram given in Fig. 4.31, the cells `E_(1) " and " E_(2)` have emf's 4 V and 8 V and internal resistances `0.5 Omega " and " 10 Omega ` respectively. Calculate the current in each resistance .

In the ciruit the cells E_1 and E_2 have emfs of 4V and 8V and internal resistance 0.5 Omega and 1.0 Omega, respectively. Calculate the current through 6 Omega resistance. ltBrgt

Two cells E_(1) and E_(2) in the circuit shown in figure, have emfs of 5 V and 9 V and internal resistance of 0.3 Omega and 1.2 Omega respestivley. Calculate the value of current flowing through the resistance of 3 Omega .

Two cells E_(1) " and " E_(2) of emfs 4 V and 8 V having internal resistances 0.5 Omega " and " 1.0 Omega respectively are connected in opposition to each other. This combination is connected in series with resistances of 4.5 Omega " and " 3.0 Omega . Another resistance is connected in parallel across the 3 Omega resistor. (a) Draw the circuit diagram (b) Calculate the total current flowing through the circuit.

In the circuit shown E, F, G and H are cells of emf 2V, 1V, 3V and 1V respectively and their internal resistance are 2Omega, 1Omega, 3Omega and 1Omega respectively.

A battery is formed by connecting three cells in series . The emfs of cells are 5 V, 2.5 V and 1.5 V and their internal resistance are 0.5 Omega ,0.05 Omega and 0.45 Omega respectively. This battery is connected across a load resistance of 5 Omega what current will be supplied by the battery ? if the cell of emf 1.5 V were connected with reverse polarity then what would have been the current supplied by the battery ?