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An electron moves in a circular orbit of...

An electron moves in a circular orbit of radius 10 cm with a constant speed of `4.0xx10^(6) ms^(-1)`. Determine the electric current at a point on the orbit.

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To determine the electric current at a point on the orbit of an electron moving in a circular path, we can follow these steps: ### Step 1: Identify the given values - Radius of the circular orbit, \( r = 10 \, \text{cm} = 0.1 \, \text{m} \) - Speed of the electron, \( v = 4.0 \times 10^6 \, \text{m/s} \) ### Step 2: Calculate the circumference of the circular orbit The circumference \( C \) of the circular orbit can be calculated using the formula: \[ C = 2 \pi r \] Substituting the radius: \[ C = 2 \pi (0.1) = 0.2 \pi \, \text{m} \approx 0.628 \, \text{m} \] ### Step 3: Calculate the time period \( T \) The time period \( T \) is the time taken to complete one full circle. It can be calculated using the formula: \[ T = \frac{C}{v} \] Substituting the values: \[ T = \frac{0.628}{4.0 \times 10^6} \approx 1.57 \times 10^{-7} \, \text{s} \] ### Step 4: Calculate the electric current \( I \) The electric current \( I \) can be calculated using the formula: \[ I = \frac{Q}{T} \] Where \( Q \) is the charge of the electron. The charge of an electron \( Q = 1.6 \times 10^{-19} \, \text{C} \). Substituting the values: \[ I = \frac{1.6 \times 10^{-19}}{1.57 \times 10^{-7}} \approx 1.02 \times 10^{-12} \, \text{A} \] ### Final Answer The electric current at a point on the orbit is approximately: \[ I \approx 1.02 \times 10^{-12} \, \text{A} \] ---
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