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Find the time of relaxation between coll...

Find the time of relaxation between collsion and free path of electrons in copper at room temperature. Given resistivity of copper`=1.7xx10^(-8) Omega`m, number density of electrons in copper `=8.5xx10^(28) m^(-3)`, charge on electron`=1.6xx10^(-19)` C, mass of electron `=9.1xx10^(-3)` kg and drift velocity of free electrons`=1.6xx10^(-4) ms^(-1)`

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The correct Answer is:
`2.5xx10^(-14)s, 4.0xx10^(-8) m`
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Find the time of relation between collision and free path of electrons in copper at room temperature .Given resistance of copper = 1.5xx 10^(-8) Omega m number density of electron in copper = 8.5 xx 10^(28)m^(-3) charge on electron = 1.6 xx 10^(19)C , mass of electrons = 9.1 xx 10^(-19) kg Drift velocity of free electron = 1.6 xx 10^(-4)ms^(-1)

The kinetic energy of an electron is 4.55 xx 10^(-25) J .The mass of electron is 9.1 xx 10^(-34) kg Calculate velocity of the electron

An electron is moving with a velocity of 10^(7) m s^(-1) . Find its energy in electron volts. (Mass of electron =9.1xx10^(-31) kg and charge of electron =1.6xx10^(-19) C )

The kinetic energy of an electron is 4.55 xx 10^(-25)J . Calculate the wavelength . [h = 6.6 xx 10^(-34)Js , mass of electron = 9.1 xx 10^(-31)kg]

Find the relaxation time for free electrons in copper, if the density of mobile electrons is 8.4 xx10^(28) m^(-3) . The resistivity of copper at room temperature is 1.7xx10^(-8)Omega m . Given : mass of electron =9.11 xx10^(-31) kg and charge on electron =1.6xx10^(-19)C .

If in a conductor number density of electrons is 8.5xx10^(28) average relaxation time 25 femtosecond mass of electron being 9.1xx10^(-31) kg, the resistivity would be of the order.

If the free electron density of copper is 8.6xx10^(28)m^(-3) and resistivity of copper at room temperature is 1.7xx10^(-6)Omega cm , find the relaxation time for the free electrons of copper. Given, mass of electron =9.1xx10^(-31) kg , and charge of electron =1.6xx10^(-19)C .

The resistivity of copper at room temperatrue is 1.7xx10^(-8) Omega m . If the free electron density of copper is 8.4xx10^(28) m^(-3) , find the relaxation time for the free electrons of copper. Given m_(e)=9.11xx10^(-31) kg and e=1.6xx10^(-19) C .

The Velocity of electrons accelerated bt potential difference of 1xx10^(4) V (the charge of the electron is 1.6xx10^(-19) C and mass is 9.11xx10^(-31) kg) is

Calculate the gyro magnetic ratio of electron (given 1.6 xx10^(-19) C, m_r=9.1xx10^(-3) kg )

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