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The diameter of the planet Jupiter is 35...

The diameter of the planet Jupiter is `3580km`. What is its angular diameter when it is at a distance of `8.25xx10^(8)km` from the earth?

Text Solution

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The correct Answer is:
`35.7''` of arc
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Knowledge Check

  • What is the approximate distance (in km) of the moon from Earth?

    A
    3,84,400
    B
    2,80,500
    C
    5,60,000
    D
    6,00,000
  • The diameter of the moon is 3.5xx10^(3)km and its distance from the earth is 3.8xx10^(5) km . It is seen by a telescope having the focal length of the objective and the eye-piece as 4m and 10cm respectively. The diameter of the image of the moon will be approximately

    A
    `2^(@)`
    B
    `20^(@)`
    C
    `40^(@)`
    D
    `50^(@)`
  • The period of revolution of a planet around the sun is 8 times that of the earth. If the mean distance of that planet from the sun is r, then mean distance of earth from the sun is

    A
    `r//2`
    B
    `2r`
    C
    `r//4`
    D
    `4r`
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    The mass of Jupiter is 314 times that of earth and the diameter of Jupiter is 11.35 times that of earth . If 'g' has a value of 9.8 ms^(-2) on the earth , what is its value on Jupiter ?

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