Find the number of molecules of `H_(2)O` is `90g` of water.

Options

A. `35.6xx10^(23)` molecules
B. `41.22xx10^(23)` molecules
C. `27.2xx10^(23)` molecules
D. `30.11xx10^(23)` molecules

Explanation

(d) `:' 18g` of `H_(2)O=6.022xx10^(23)` molecules
`:. 1g` of `H_(2)O=(6.022xx10^(23))/18`
`:. 90g` of `H_(2)O=(6.022xx10^(23))/18xx90`
`=30.110xx10^(23)` molecules