The energy of a photon depends upon Planck's constant and frequency of light. Find the exprression for photon energy.

Options

A. `E=hv`
B. `E=h/v`
C. `E=v/h`
D. `E=hv^(2)`

Explanation

(a) `E=h^(a).v^(b)`…………..(i)
where `h=` Planck's constant and `v=` frequency
`[E]=[ML^(2)T^(-2)],[v]=[M^(0)L^(0)T^(-1)]` and `[h]=[ML^(2)T^(-1)]`
From Eq. (i) `[ML^(2)T^(-2)]=[ML^(2)T^(-1)]^(a)[M^(0)L^(0)T^(-1)]^(b)`
`[ML^(2)T^(-2)]=[M^(3)L^(2a)T^(-a-b)]`
`implies a=1` and `-a-b=-2impliesa+b=2impliesb=1`
`impliesE=hv`