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The radius of nucleus is r=r(0)A^(1//3),...

The radius of nucleus is `r=r_(0)A^(1//3)`, where `A` is mass number. The dimensions of `r_(0)` is

A

`[MLT^(-2)]`

B

`[M^(0)L^(0)T^(-1)]`

C

`[M^(0)LT^(0)]`

D

None of these

Text Solution

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C
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Which of the following is corect regarding nucleus? (i) The radius of nucleus R = R_(0)A^(1//3) where R_(0) = 1.1xx10^(-15)m, A = mass number (ii) the density of nucleus = rho=(M)/(V) = (mA)/((4)/(3)piR^(3)) m: mass of proton or neutron (iii) Nucleus stability depends on neutron-proton ratio N//Z N//Z ~= .6 for heaviest stable nucleus (iv) The total angular momentum of the nucleus is the resultant of all the spin and orbital angular momenta of the individual nucleon (nucleon means either proton or neutron). The total angular momentum of a nucleus is called the nuclear spin of that nucleus.

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