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The velocity of particle is v=v(0)+"gt"+...

The velocity of particle is `v=v_(0)+"gt"+ft^(2)`. If its position is `x=0` at `t=0` then its displacement after unit time `(t=1)` is

A

`v_(0)+2g+3f`

B

`v_(0)+g/2+f/3`

C

`v_(0)+g+f`

D

`v_(0)+g/2+f`

Text Solution

AI Generated Solution

To solve the problem, we need to find the displacement of the particle after 1 second given its velocity function and initial conditions. ### Step-by-Step Solution: 1. **Understand the given information**: - The velocity of the particle is given by the equation: \[ v = v_0 + gt + ft^2 ...
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