A balloon going upward with a velocity of `12m//s` is at a height of `65m` from the earthh surface at any instant. Exactly at this instant a packet drops from it. How much time will the packet take in reaching the surface of earth?(Take `g=10m//s^(2)`)

Options

A. `75s`
B. `10s`
C. `5s`
D. none of these

Explanation

To solve the problem, we need to determine how long it takes for a packet dropped from a balloon (which is moving upward) to reach the surface of the Earth.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Initial velocity of the packet (u) = 12 m/s (upward)
- Height from which the packet is dropped (s) = 65 m (downward)
- Acceleration due to gravity (g) = 10 m/s² (downward)
...