A ball projected from ground at an angle of `45^(@)` just clears a wall infront. If point of projection is `4m` from the foot of wall and ball strikes the ground at a distance of `6m` on the other side of the wall, the height of the wall is

Options

A. `4.4m`
B. `2.4m`
C. `3.6m`
D. `1.6m`

Explanation

To solve the problem step by step, we will use the principles of projectile motion.

### Step 1: Understand the Problem
We have a ball projected at an angle of 45 degrees from the ground. The ball just clears a wall that is 4 meters away from the point of projection and lands 6 meters beyond the wall. We need to find the height of the wall.

### Step 2: Determine the Total Distance
The total horizontal distance covered by the ball is:
\[ \text{Total distance} = \text{Distance to wall} + \text{Distance beyond wall} = 4 \, \text{m} + 6 \, \text{m} = 10 \, \text{m} \]
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