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A man runs at a speed of 4m//s to overta...

A man runs at a speed of `4m//s` to overtake a standing bus. When he is `6m` beind the door at `t=0`, the bus mover forward and continuous with a constant acceleration of `1.2m//s^(2)`. The man reaches the door in time `t`. Then

A

`4t=6+0.6t^(2)`

B

`1.2t^(2)=4t`

C

`4t^(2)=1.2t`

D

`6+4t=0.2t^(2)`

Text Solution

Verified by Experts

(a) Let us draw the figure for given situation,

`implies4t=6+1/2xx1.2xxt^(2)`
`implies 4t=6+0.6t^(2)`
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