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A body covers a total distance of 3s. Th...

A body covers a total distance of `3s`. The first `s` is covered with a velocity `u` the second `s` with `V` and the last `s` with `omega`. Then, the average velocity during the whole journey is

A

`(u+v+omega)/3`

B

`(3uvomega)/(u+v+omega)`

C

`(3uvomega)/(uv+vomega+uomega)`

D

zero

Text Solution

Verified by Experts

(c) Avery velocity `v_(av)=("Total distance")/(Total time")`
`impliesv_(av)=(s+s+s)/(s/u+s/v+s/(omega))impliesv_(av)=(3uv omega)/(uv+vomega+uomega)`
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