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A particle executing simple harmonic mot...

A particle executing simple harmonic motion has amplitude of `1 m` and time period `2 s` at `t = 0`, net force on the particle is zero. Find the equation of displacement of the particle.

A

x = sin`pit`

B

x=cos`pit`

C

x=sin 2 `pit`

D

`x=cos2pit`

Text Solution

Verified by Experts

The correct Answer is:
A
`therefore` In the case of SHM,
`x=a sin(omegat+phi)`
Here, `a=1m, omega=(2pi)/(T)=(2pi)/(2)=pi "rad"//s`
At t = 0,net force on the particle is zero
Hence, particle is at mean position at t = 0
`therefore" "x = 0 "at" t = 0`
`therefore" "0=a sin(omegaxx0+phi)rArrphi=0`
`therefore" "x=a sin omega t`
`therefore" "x=1xxsin pi t`
`therefore" "x=sin pit`
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