Home
Class 11
PHYSICS
A particle executes simple harmonic moti...

A particle executes simple harmonic motion. The amplitude of vibration of particle is 2 cm. The displacement of particle in one time period is

A

1 cm

B

2 cm

C

4 cm

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D

`because x=A sin omegat`
`therefore" "x=Asin((2pi)/(T)xxT)`
`therefore" "x=A sin 2pi=0`
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    BITSAT GUIDE|Exercise BITSAT Archives|12 Videos
  • SCALARS AND VECTORS

    BITSAT GUIDE|Exercise All Questions|34 Videos
  • TRANSMISSION

    BITSAT GUIDE|Exercise All Questions|38 Videos

Similar Questions

Explore conceptually related problems

If a particle is executing simple harmonic motion, then acceleration of particle

While a particle executes linear simple harmonic motion

A particle executes simple harmonic motion. Then the graph of veloctiy as a function of its displacement is

A particle is executing simple harmonic motion with an amplitude A and time period T. The displacement of the particles after 2T period from its initial position is

For a particle executing simple harmonic motion, the acceleration is proportional to

A particle executes simple harmonic motion with an amplitude of 5cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then its periodic time in seconds is :

For a particle executing simple harmonic motion, the amplitude is A and time period is T. The maximum speed will be

A particle executes simple harmonic motion of amplitude A. At what points is its speed half the maximum speed ?

A particle executes linear simple harmonic motion with an amplitude of 3 cm . When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is