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A particle executes simple harmonic moti...

A particle executes simple harmonic motion with a frequency f. The frequency with which the potential. Energy oscillates is

A

f

B

f/2

C

2f

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
If `x=A sin omegat`
Then, `PE=(1)/(2)mA^(2)omega^(2)sin^(2)omegat`
`therefore" "PE=(1)/(2)mA^(2)omega^(2)((1-cos2omegat)/(2))`
`therefore" "omega'=2omega`
or `2pif'=2xx2pif`
`therefore" "f'=2f`
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