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A point mass x = 20 kg, is suspended by ...

A point mass x = 20 kg, is suspended by a massless spring of constant 2000 N/m. The point mass is released when elongation in the spring is 15 cm. The equation of displacement of particle as function of time is (take, g =`10m//s^(2)`)

A

y = 10 sin 10t

B

Y = 10 cos 10t

C

`y=10 sin(10t+(pi)/(6))`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
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