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A spring of force constant k is cut into...

A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of

A

`(2)/(3)k`

B

`(3)/(2)k`

C

3k

D

6k

Text Solution

Verified by Experts

The correct Answer is:
B
`(1)/(k)=(1)/(k_(1))+(1)/(k_(2))or (1)/(k)=(2)/(k_(2))+(1)/(k_(2))=(3)/(k_(2))`
`because" "k_(2)=3k`
`because" "k_(1)=(k_(2))/(2)=(3)/(2)k`
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