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Two point masses of 3.0kg and 1.0kg are ...

Two point masses of `3.0kg` and `1.0kg` are attached to opposite ends of a horizontal spring whose spring constant is `3Nm^(-1)` as shown in figure . The natural frequency of vibration so this system is `n//piHz`. Find the integral value of `n`.

A

4 Hz

B

3 Hz

C

2 Hz

D

1 Hz

Text Solution

Verified by Experts

The correct Answer is:
B
The reduced mass of the system is `mu=(m_(1)m_(2))/(m_(1)+m_(2))`
`T=2pisqrt(((mu)/(k)))=2pisqrt([(m_(1)m_(2))/((m_(1)+m_(2))k)])`
`therefore" "f=(1)/(T)=3Hz`
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