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A clock with an iron pendulum keeps corr...

A clock with an iron pendulum keeps correct time at `20^(@)C`. How much time will it lose or gain in a day if the temperature changes to `40^(@)C`. Thermal coefficient of liner expansion `alpha = 0.000012 per^(@)C`.

A

`10.3`s/day

B

19s/day

C

`5.5`s/day

D

`6.8`s/day

Text Solution

Verified by Experts

The correct Answer is:
A
`(Deltat)/(t)=(1)/(2)(DeltaL)/(2)=(1)/(2)alphaDeltatheta`
`=(1)/(2)xx12xx10^(-6)xx(40^(@)-20^(@))=12xx10^(-5)`
`Deltat=txx12xx10^(-5)=86400xx12xx10^(-5)=10.3s//day`
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