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If the displacement of simple pendulum a...

If the displacement of simple pendulum at any time is `0.02` m and acceleration is `2m//s^(2)`, then in this time angular velocity will be

A

100 rad/s

B

10 rad/s

C

1 rad/s

D

`0.1` rad/s

Text Solution

Verified by Experts

The correct Answer is:
B
Acceleration `|alpha|=omega^(2)x`
or `omega=sqrt(alpha)/(x)`
`=sqrt((2)/(0.002))=10rad//s`
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