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In (Q. 10.) the ratio of particle veloci...

In (Q. 10.) the ratio of particle velocity amplitude and wavelength is

A

`pi`

B

`2pi`

C

`3pi`

D

`4pi`

Text Solution

Verified by Experts

The correct Answer is:
D
We know that,
`k=(2pi)/(100)`
or `(2pi)/(lambda)=(2pi)/(100)`
`therefore " "lambda = 100 cm`
But `v_("Particle")=(del y)/(del t) = a omega cos (omega t - kx)`
`(v_("Particle"))_("max")= a omega = 4 xx (2pi)/(0.02)=400 pi cm//s`
`therefore " "(v_("Particle"))_("max")/(lambda)=(400 pi)/(100)= 4pi`
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