Along a stretched string equation of transverse wave is `y = 3 sin [2pi ((x)/(20)-(t)/(0.01))]`
Where, x, y are in cm and t is in second. Calculate wave velocity.

Options

A. 20 m/s
B. 30 m/s
C. 15 m/s
D. 25 m/s

Answer

A

Explanation

Let wave velocity = v
`v = lambda f`
The given equation of wave
`y = 3 sin [2pi((x)/(20)-(t)/(0.01))]`
Compare the given equation with standard equation
`y = A sin [2pi ((x)/(lambda)-(t)/(T))]`
We get A = 3 cm
`lambda = 20 cm`
`f=(1)/(T) = 100 Hz`
`v = lambda f = (20 xx 100)/(100)=20 m//s`