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A travelling wave is described by the eq...

A travelling wave is described by the equation `y = y_(0) sin ((ft - (x)/lambda))`. The maximum particle velocity is equal to four times the wave velocity if

A

`y_(0)pi`

B

`(y_(0)pi)/(2)`

C

`2y_(0)pi`

D

`1.5 y_(0)pi`

Text Solution

Verified by Experts

The correct Answer is:
B
`omega = 2pi f " and "v_("max")=omegar = 2pify_(0)`
Wave velocity `= f lambda`
`2pi fy_(0) = 4f lambda`
(Given, velocity of particle is four times of wave velocity)
`lambda = (y_(0)pi)/(2)`
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