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The time taken by a transverse wave goin...

The time taken by a transverse wave going on a wire having mass 5 g, form one end to another end of wire is 0.5 s. The area of cross-section fo wire is `1 mm^(2)` and Young's modulus of elasticity is `16 xx 10^(11) N//m^(2)`. The speed of wave is 80 m/s. The strain in wire is

A

`5 xx 10^(-7)`

B

`2 xx 10^(-7)`

C

`3 xx 10^(-6)`

D

`4 xx 10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
A
`c = sqrt(((T)/(mu)))`
`therefore " "T=muc^(2),y=(T)/(A " strain")`
`therefore` Strain = `(T)/(AY)=(muc^(2))/(AY)=(mc^(2))/(lAY)`
`=(mc^(2))/((ct)AY) = (mc)/(AYt) = (5xx10^(-3)xx80)/(10^(-6)xx16xx10^(11)xx0.5)`
`= 5 xx 10^(-7)`
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