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If a string is stretched with a weight 4...

If a string is stretched with a weight 4 kg then the fundamental frequency is equal to 256 Hz. What weight is needed to produce its octave?

A

4 kg-wt

B

12 kg-wt

C

16 kg-wt

D

24 kg-wt

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the relationship between the fundamental frequency of a stretched string and the tension in the string. ### Step 1: Understand the relationship between frequency and tension The fundamental frequency (F) of a string is given by the formula: \[ F \propto \sqrt{\frac{T}{\mu}} \] where: - \( T \) is the tension in the string, - \( \mu \) is the linear mass density of the string (which remains constant in this case). ### Step 2: Establish the relationship for the two frequencies Given that the fundamental frequency with a weight of 4 kg is 256 Hz, we want to find the weight needed to produce its octave. The octave means that the second frequency (F2) is double the first frequency (F1): \[ F_2 = 2F_1 \] ### Step 3: Set up the ratio of frequencies From the relationship of frequencies and tension, we can write: \[ \frac{F_1}{F_2} = \sqrt{\frac{T_1}{T_2}} \] Substituting \( F_2 = 2F_1 \): \[ \frac{F_1}{2F_1} = \sqrt{\frac{T_1}{T_2}} \] This simplifies to: \[ \frac{1}{2} = \sqrt{\frac{T_1}{T_2}} \] ### Step 4: Square both sides to eliminate the square root Squaring both sides gives: \[ \left(\frac{1}{2}\right)^2 = \frac{T_1}{T_2} \] \[ \frac{1}{4} = \frac{T_1}{T_2} \] ### Step 5: Express tensions in terms of weights The tension in the string is equal to the weight hanging from it. Therefore: - \( T_1 = 4 \, \text{kg} \times g \) (where \( g \) is the acceleration due to gravity) - \( T_2 = W \, \text{kg} \times g \) (where \( W \) is the new weight we want to find) Substituting these into the equation gives: \[ \frac{1}{4} = \frac{4g}{Wg} \] The \( g \) cancels out: \[ \frac{1}{4} = \frac{4}{W} \] ### Step 6: Solve for W Cross-multiplying gives: \[ W = 4 \times 4 = 16 \, \text{kg} \] ### Conclusion To produce the octave of the fundamental frequency of 256 Hz, a weight of **16 kg** is needed.

To solve the problem step by step, we will use the relationship between the fundamental frequency of a stretched string and the tension in the string. ### Step 1: Understand the relationship between frequency and tension The fundamental frequency (F) of a string is given by the formula: \[ F \propto \sqrt{\frac{T}{\mu}} \] where: - \( T \) is the tension in the string, - \( \mu \) is the linear mass density of the string (which remains constant in this case). ...
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