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The temperature and the surface area of ...

The temperature and the surface area of the body are `227^(@)C` and `0.15 m` respectively. If its transmitting power is negligible and reflecting power is `0.5`, then calculate the thermal power of the body.
(Given `sigma-5.67xx10^(-4)J//m^(2)//s//K`)

A

`300W`

B

`265.78W`

C

`201W`

D

`320.89W`

Text Solution

Verified by Experts

(b) Absorbing power of a body is equal to emissivity of the body.
And also `a+r+t=1implies0+0.5+a=1`
`a=0.5, epsilona=0.5`
`Q/t=epsilon sigma AT^(4)=(0.5)(5.67)xx10^(-8)(0.15)xx(273+227)^(4)`
`Q/t=265.78W`
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