An electromagnetic radiation of frequency v, wavelength `lamda`, travelling with velocity c in air, enters a glass slab of refractive index `mu`. The frequency, wavelength and velocity of light in the glass slab will be respectively.

Options

A. `n/(mu),(lamda)/(mu),v/(mu)`
B. `n,(lamda)/(mu),v/(mu)`
C. `n,lamda,v/(mu)`
D. `n/(mu),(lamda)/(mu),v`

Explanation

(b) In going form one medium to another, frequency remains same but wavelength and velocity decreases with the increase in refractive index i.e. wavelength becomes `lamda'=(lamda)/(mu)` and velocity becomes `v'=v/(mu)`.