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The maximum value of index of refraction...

The maximum value of index of refraction of a material of a prism which allows the passage of light through it when the refracting angle of prism is A is

A

`sqrt(1+sin(A/2))`

B

`sqrt(1+cos(A/2))`

C

`sqrt(1+tan^(2)(A/2))`

D

`sqrt(1+cot^(2)(A/2))`

Text Solution

Verified by Experts

(d) Situation is shown in figure.
`r_(1)=C,r_(2)=C`
`r_(1)+r_(2)=A`
`:.2C=A,C=A/2`
`:.mu=1/(sin C)=1/(sin (A/2))`
`=(sqrt(sin^(2)(A/2)+cos^(2)(A/2)))/(sin (A/2))=sqrt(1+cot^(2)(A/2))`
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