How many moels of AgCI would be obtained, when 100 mL of `0.1` M `CO(NH_(3))_(5)CI_(3)` is treated with excess of `AgNO_(3)`?

Options

A. `0.01`
B. `0.02`
C. `0.03`
D. None of thses

Explanation

(b) `[Co(NH_(3))_(5)CI]CI_(3)` is an octahedral complex ionising in aqueous solutions as
`[Co(NH_(3))_(5)CI]CIrarr[Co(NH_(3))_(5)CI]^(2+)+2CI^(-)`
Moles of `[Co(NH_(3))_(5)CI]CI_(2)=(0.1)/(1000)xx100=0.01`
Moles of AgCI formed `=2xx` moles of `CI^(-)` in complex `=0.01xx2=0.02`