Home
Class 12
PHYSICS
A parallel plate capacitor has two layer...

A parallel plate capacitor has two layers of dielectrons as shown in figure. This capacitor is connected across a battery, then the ratio of potential difference across the dielectric layers is

A

`(4)/(3)`

B

`(1)/(2)`

C

`(1)/(3)`

D

`(3)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

As it is a series combination, so charge on each capacitor is same

So, `V_(1) = (Q)/(C_(1))` and `V_(2) = (Q)/(C_(2))`
`rArr = (V_(1))/(V_(2)) = (C_(2))/(C_(1)) = (epsilon_(0)K_(2)(A)/(2d))(epsilon_(0)K_(1)(A)/(d)) = (6)/(2xx2) = (3)/(2)`
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC CAPACITOR

    BITSAT GUIDE|Exercise BITSAT archives|6 Videos
  • CURRENT ELECTRICITY

    BITSAT GUIDE|Exercise Bitsat Archives|26 Videos
  • ELECTRIC CHARGE

    BITSAT GUIDE|Exercise All Questions|28 Videos

Similar Questions

Explore conceptually related problems

A parallel plate capacitor has two layers of dielectric as shown in figure. This capacitor is connected across a battery. The graph which shows the variation of electric field (E) and distance (X) from left plate.

Each plate of a parallel plate capacitor has a charge q on it. The capacitor is now connected to a battery. Now,

The displacement current flows in the dielectric of a capacitor when the potential difference across its plates-

In the circuit diagram find the potential difference across the plates of capacitor C

Assertion: When an uncharged capacitor is connected across a battery, half the work done by the battery is stored as electric potential energy inside the capacitor and remaining half is dissipated in the form of heat. Reason: When an uncharged capacitor is connected across the battery then potential difference between the plates of capacitor increases from zero to the value of EMF of battery but battery supplies charge at the constant potential difference.

Five capacitors are connected across a battery of 5V as shown in figure (o). Calculate the potential difference across the plates of the 5muF capacitor.

The plates of a parallel plate capacitor are charged to a potential difference of 117 V and then connected across a resistor. The potential difference across the capacitor decreases exponentially with to time.After 1s the potential difference between the plates is 39 V, then after 2s from the start, the potential difference (in V) between the plates is

In a ircuit shown in figure, the potential difference across the capacitor of 2muF is

In the circuit shown in the figure, the potential difference across the 4.5 muF capacitor is