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Capacitance of a capacitor made by a thi...

Capacitance of a capacitor made by a thin metal foil is `2 muF`. If the foil is foilded with paper of thickness 0.15 mm, dielectric constant of paper is 2.5 and width of paper is 400 mm, the length of foil will be

A

0.34 m

B

1.33 m

C

13.4 m

D

33.9 m

Text Solution

Verified by Experts

The correct Answer is:
D
If length of the foil is l, then `C = (Kepsilon_(0)(lxxb))/(d)`
`rArr 2xx10^(-6) = (2.5xx8.85xx10^(-12)(lxx400xx10^(-3)))/(0.01xx10^(-3))`
`l = 33.9 m`
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