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The threshold wavelength for the ejectio...

The threshold wavelength for the ejection of electron from metal is 330 nm, then work function for the photoelectric emission is

A

`6xx10^(-12)` J

B

`6xx10^(-19)` J

C

`1.2xx10^(-20)` J

D

`1.2xx10^(-18)` J

Text Solution

Verified by Experts

The correct Answer is:
B
`W=hv_(0)`
`W=(hc)/lambda_(0)=(6.62xx10^(-34)xx3xx10^(8))/(330xx10^(-9))=6xx10^(-19)` J
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