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The potential energy of the electron in ...

The potential energy of the electron in the hydrogen atom is `-6.8 eV` The excited state in which the eletron is present is

A

first

B

second

C

third

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Total energy `=E_(n)=1/2` (Potential energy)
`E_(n)=(-6.8)/2=-3.4` eV
We know tha t `E_(n)=-(13.6eV)/n^(2)`
`-3.4 eV=(-13.6 eV)/n^(2)`
`n^(2)=4`
`n=2` First excited state
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