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The electron of hydrogen atom is excited...

The electron of hydrogen atom is excited to certain level. When the electron returns to the first Bohr orbit, the wavelength of line emitted if the energy difference is 11.0 eV would be

A

`11.25xx10^(-7)m`

B

`2.2xx10^(-6)m`

C

`9.1176xx10^(-8)m`

D

`1.22xx10^(-7)m`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(2)-E_(1)=DeltaE=(hc)/lambda`
`lambda=(hc)/(DeltaE)=(6.62xx10^(-34)xx3xx10^(8))/(11.0xx1.6xx10^(-19))`
`lambda =11.25xx10^(-7)`m
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