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Ionisation energy of He^+ is 19.6 xx 10^...

Ionisation energy of `He^+` is `19.6 xx 10^-18 J "atom"^(-1)`. The energy of the first stationary state `(n = 1)` of `Li^( 2 +)` is.

A

`4.41xx10^(-16)J atom^(-1)`

B

`-4.41xx10^(-17) J atom^(-1)`

C

`-2.2xx10^(-15)J atom^(-1)`

D

`8.82xx10^(-17)J atom^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`IE=-E_(1)`
`E_(1) for He^(+)=-19.6xx10^(-18)Jat om ^(-1)`
`(E_(1))_(He^(+))/((E_(1))_(Li^(2+)))=(Z_(He^(+)))^(2)/((Z_(Li^(2+)))^(2))rArr (-19.6xx10^(-18))/((E_(1))_(Li^(2+)))=4/9`
`E_(1)(Li^(2+))=(-19.6xx9xx10^(-18))/4`
`-4.41xx10^(-17)Jat om^(-1)`
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